文件名称:lab02

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f(n)=f(n-1)+f(n-2) f(0)=f(1)=1,求斐波那契数列第20项,分别用循环和递归的方式,比较时间效率。提示:可以使用c函数clock取出当前系统时间,计算前后各一次,两次相减除以每秒的时钟数,就可以得到以秒为单位的差距-f (n) = f (n-1)+ f (n-2) f (0) = f (1) = 1, Item 20 seeking Fibonacci number Fibonacci sequence that were circulating and recursively, more time effectiveness. Tip: You can use the c function Remove the current system clock time, before and after the calculation each time, twice per second relative to the clock deduction, you can get in seconds gap
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下载文件列表





lab02\Debug\lab02.exe

.....\.....\lab02.ilk

.....\.....\lab02.pdb

.....\ipch\lab02-e13a106c\lab02-9aca239d.ipch

.....\lab02\Debug\CL.read.1.tlog

.....\.....\.....\CL.write.1.tlog

.....\.....\.....\lab02.exe.embed.manifest

.....\.....\.....\lab02.exe.embed.manifest.res

.....\.....\.....\lab02.exe.intermediate.manifest

.....\.....\.....\lab02.lastbuildstate

.....\.....\.....\lab02.log

.....\.....\.....\lab02.obj

.....\.....\.....\lab02.pch

.....\.....\.....\lab02_manifest.rc

.....\.....\.....\link-cvtres.read.1.tlog

.....\.....\.....\link-cvtres.write.1.tlog

.....\.....\.....\link.8352-cvtres.read.1.tlog

.....\.....\.....\link.8352-cvtres.write.1.tlog

.....\.....\.....\link.8352.read.1.tlog

.....\.....\.....\link.8352.write.1.tlog

.....\.....\.....\link.read.1.tlog

.....\.....\.....\link.write.1.tlog

.....\.....\.....\mt.read.1.tlog

.....\.....\.....\mt.write.1.tlog

.....\.....\.....\rc.read.1.tlog

.....\.....\.....\rc.write.1.tlog

.....\.....\.....\stdafx.obj

.....\.....\.....\vc100.idb

.....\.....\.....\vc100.pdb

.....\.....\lab02.cpp

.....\.....\lab02.vcxproj

.....\.....\lab02.vcxproj.filters

.....\.....\lab02.vcxproj.user

.....\.....\ReadMe.txt

.....\.....\stdafx.cpp

.....\.....\stdafx.h

.....\.....\targetver.h

.....\lab02.sdf

.....\lab02.sln

.....\lab02.suo

.....\ipch\lab02-e13a106c

.....\lab02\Debug

.....\Debug

.....\ipch

.....\lab02

lab02

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