文件名称:jinyibuxuexiluojiyunsuan
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知识要点：理解熟悉单片机的逻辑运算
运行结果：P1 口输出结果为01100000,注意1 为灭0 为亮,从1.7 到1.0 排列
ANL 0FH就是把数据与00001111相与那么遇1得原来的数遇0则为0,结果是前面的4位变
0, 后面的4 位保留-knowledge points : understanding the logic familiar with the MCU running Operational Results : P1 output to 01.1 million, for the attention of an anti-0. from 1.7 to 1.0 with ANL 0FH data is 00001111 and then phase in the case of an original few were 0 0 encountered, the results of the previous four variable 0, behind the four reservations
运行结果：P1 口输出结果为01100000,注意1 为灭0 为亮,从1.7 到1.0 排列
ANL 0FH就是把数据与00001111相与那么遇1得原来的数遇0则为0,结果是前面的4位变
0, 后面的4 位保留-knowledge points : understanding the logic familiar with the MCU running Operational Results : P1 output to 01.1 million, for the attention of an anti-0. from 1.7 to 1.0 with ANL 0FH data is 00001111 and then phase in the case of an original few were 0 0 encountered, the results of the previous four variable 0, behind the four reservations
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压缩包 : 51622430jinyibuxuexiluojiyunsuan.rar 列表 进一步学习单片机的逻辑运算.doc