文件名称:jisuan
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用复化梯形公式和复化辛卜生公式计算积分
I_1 (f)=∫_0^(π/2)?√(1+cos^2?x ) dx和I_2 (f)=∫_0^(π/2)?〖tan?x/x dx〗
观察n为多少时，所得近似值有6位有效数字。
-Compound trapezoid formula and complexification Xinbo Health formula calculated integral I_1 (f) = ∫ _0 ^ (π/2) ? √ (1+cos ^ 2 ? x) dx and I_2 (f) = ∫ _0 ^ (π/2) ? The 〖tan ? x/x dx〗 observed n is the number obtained approximation of six significant digits.
I_1 (f)=∫_0^(π/2)?√(1+cos^2?x ) dx和I_2 (f)=∫_0^(π/2)?〖tan?x/x dx〗
观察n为多少时，所得近似值有6位有效数字。
-Compound trapezoid formula and complexification Xinbo Health formula calculated integral I_1 (f) = ∫ _0 ^ (π/2) ? √ (1+cos ^ 2 ? x) dx and I_2 (f) = ∫ _0 ^ (π/2) ? The 〖tan ? x/x dx〗 observed n is the number obtained approximation of six significant digits.
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jisuan.cpp