文件名称:C-Programming-Language-100-cases
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文件包含100个C语言程序的例子,由易到难,可以帮助初学者提高学习效率。注:1、2、3、4个数字,有多少能形成一个不同于彼此,没有重复数字三位数吗?是多少? 1。这个程序分析:能填补一百年,十,比特数1、2、3、4。所有的安排后再删除不满足条件的安排。
2.程序源码为:
main()
{
int i,j,k
printf("\n")
for(i=1 i<5 i++)
for(j=1 j<5 j++)
for (k=1 k<5 k++)
{
if (i!=k&&i!=j&&j!=k) printf(" d, d, d\n",i,j,k)
}
}
-File consists of 100 C program example, from easy to difficult, can help beginners improve the learning efficiency.Topic: 1, 2, 3, 4 Numbers, how many can form a different from each other and have no the repeat number three digits? How much be?1. The program analysis: can fill in one hundred, ten, bit number is 1, 2, 3, 4. Of all the arrangement of remove not meet again after the arrangement of the condition.
2. The source code:
main()
{
int i,j,k
printf("\n")
for(i=1 i<5 i++)
for(j=1 j<5 j++)
for (k=1 k<5 k++)
{
if (i!=k&&i!=j&&j!=k) printf(" d, d, d\n",i,j,k)
}
}
……
2.程序源码为:
main()
{
int i,j,k
printf("\n")
for(i=1 i<5 i++)
for(j=1 j<5 j++)
for (k=1 k<5 k++)
{
if (i!=k&&i!=j&&j!=k) printf(" d, d, d\n",i,j,k)
}
}
-File consists of 100 C program example, from easy to difficult, can help beginners improve the learning efficiency.Topic: 1, 2, 3, 4 Numbers, how many can form a different from each other and have no the repeat number three digits? How much be?1. The program analysis: can fill in one hundred, ten, bit number is 1, 2, 3, 4. Of all the arrangement of remove not meet again after the arrangement of the condition.
2. The source code:
main()
{
int i,j,k
printf("\n")
for(i=1 i<5 i++)
for(j=1 j<5 j++)
for (k=1 k<5 k++)
{
if (i!=k&&i!=j&&j!=k) printf(" d, d, d\n",i,j,k)
}
}
……
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下载文件列表
C Programming Language 100 cases\C Programming Language 100 cases.pdf
C Programming Language 100 cases
C Programming Language 100 cases