文件名称:Power-Network
- 所属分类：
- Internet/网络编程
- 资源属性：
- [WORD]
- 上传时间：
- 2012-11-26
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- 31kb
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- 0次
- 提 供 者：
- 陈*
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这个题目可以采用网络流的模型来解决。
在原图的基础上添加一个源点和汇点。对于每个Power Station，从源点引一条容量为pmax的弧；对于每个Consumer，引一条容量为cmax的弧到汇点；对于题目中给的三元组(u,v)z，从点u连一条容量为z的弧到点v。显然这样构图是满足题目要求的。然后求这个网络的最大流即可。
-The subject of network flow can be used to solve the model.
On the basis of the add a point of origin and one world. For each Power Station, from the point of origin lead a capacity for pmax arc For each Consumer, lead a capacity for cmax arc to one world For the questions in three yuan to group (u, v) z, from some u even have a capacity for z along the arc v. Apparently this composition is to meet the requirements of the subject. And then for the network s maximum flow can.
在原图的基础上添加一个源点和汇点。对于每个Power Station，从源点引一条容量为pmax的弧；对于每个Consumer，引一条容量为cmax的弧到汇点；对于题目中给的三元组(u,v)z，从点u连一条容量为z的弧到点v。显然这样构图是满足题目要求的。然后求这个网络的最大流即可。
-The subject of network flow can be used to solve the model.
On the basis of the add a point of origin and one world. For each Power Station, from the point of origin lead a capacity for pmax arc For each Consumer, lead a capacity for cmax arc to one world For the questions in three yuan to group (u, v) z, from some u even have a capacity for z along the arc v. Apparently this composition is to meet the requirements of the subject. And then for the network s maximum flow can.
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Power Network.doc