序列的频数检验，判断任意一个序列是否能通过频数检验：

对序列的每一位，可能的取值只有是0、1。

 频数分布表为：

(n0+n1=n—序列长度（位长度）)





 计算皮尔逊统计量：

 查概率书中的统计表，取显著水平a=5 ，或1 ，或0.5 等，通过查自由度为1的 2-分布表得到相应的阈值 a。

 判定：如果   a，则通过该项检验；否则，不能通过。

-Frequency sequence test to determine whether a sequence through any inspection frequency: every one of the sequences, the possible values is only 0,1. 　frequency distribution table: (n0+ n1 = n-sequence length (bit length)) 　calculated Pearson statistic: 　check the probability tables in the book, take a significant level a = 5 , or 1 , or 0.5　 and so on, through the investigation of 1 degree of freedom of 　2- distribution table corresponding threshold 　a. 　determine: If 　　　a, then through the test　otherwise, can not.