文件名称:diedaifa
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// 编程序 用迭代法求a的立方根,求立方根的迭代公式为 ::Xi+1=（2*Xi）/3+a/(3*Xi*Xi) 假定X的初值为a,迭代到|Xi+1-Xi|<10的-5次方为止. 显示a=3,27的值,并通过调用pow(a,1.0/3)函数加以验证.。-//Compile a program with Iteration Method and the cube root, find the cube root of the iteration formula is:: Xi+1 = (2* Xi)/3+ a/(3* Xi* Xi) assumes that the initial value of X is a iteration to | Xi+1- Xi | < 10 the-5 power up. shows the value of a = 3,27, and by calling pow (a, 1.0/3) function to be verified..
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die dai fa.cpp