文件名称:gcd
- 所属分类:
- 加密解密
- 资源属性:
- [Windows] [Visual.Net] [源码]
- 上传时间:
- 2012-11-26
- 文件大小:
- 495kb
- 下载次数:
- 0次
- 提 供 者:
- J***
- 相关连接:
- 无
- 下载说明:
- 别用迅雷下载,失败请重下,重下不扣分!
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The greatest common divisor of integers x and y is the largest integer that evenly divides both x and y. Write a recursive function gcd that returns the greatest common divisor of x and y, define recursively as follows. It y is equal to 0, then gcd(x,y) is x otherwise, gcd(x, y) is gcd(y, x y), where is the modulus function. [Note: For this algorithm, x must be larger than y.] Write a driver program ( main() function ) to test your function.-The greatest common divisor of integers x and y is the largest integer that evenly divides both x and y. Write a recursive function gcd that returns the greatest common divisor of x and y, define recursively as follows. It y is equal to 0, then gcd(x,y) is x otherwise, gcd(x, y) is gcd(y, x y), where is the modulus function. [Note: For this algorithm, x must be larger than y.] Write a driver program ( main() function ) to test your function.
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下载文件列表
981235\981235\981235.cpp
......\......\981235.vcproj
......\......\981235.vcproj.YOUMEIKETSU.Administrator.user
......\......\Debug\981235.exe.embed.manifest
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......\......\.....\vc90.idb
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......\981235.ncb
......\981235.sln
......\981235.suo
......\Debug\981235.exe
......\.....\981235.ilk
......\.....\981235.pdb
......\981235\Debug
......\981235
......\Debug
981235
......\......\981235.vcproj
......\......\981235.vcproj.YOUMEIKETSU.Administrator.user
......\......\Debug\981235.exe.embed.manifest
......\......\.....\981235.exe.embed.manifest.res
......\......\.....\981235.exe.intermediate.manifest
......\......\.....\981235.obj
......\......\.....\BuildLog.htm
......\......\.....\mt.dep
......\......\.....\vc90.idb
......\......\.....\vc90.pdb
......\981235.ncb
......\981235.sln
......\981235.suo
......\Debug\981235.exe
......\.....\981235.ilk
......\.....\981235.pdb
......\981235\Debug
......\981235
......\Debug
981235