文件名称:2
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2. 用循环链表解Josephus问题。设有n个人围坐在一个圆桌周围,现从第1个人开始报数,数到第m的人出列,然后从出列的下一个人重新开始报数,数到第m的人又出列,…,如此反复直到所有的人全部出列为止。Josephus问题是:对于任意给定的n和m,求出按出列次序得到的n个人员的序列-2. Josephus solution of the problem with the circulation list. With n individuals sitting around a round table is started by a report from the first number, the number of people out to the first m columns, and then from the next person out of the column began to count off again, several to the first m out of those people who have column, ..., and so forth until all of the columns were all out of date. Josephus The question is: For any given n and m, find out the columns according to the order received sequence of n-persons
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