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十进制N和其它进制数的转换是计算机实现计算的基本问题,其解决方法很多,其中一个简单算法基于下列原理:
N=(N div d)*d+ N mod d ( 其中:div为整除运算,mod为求余运算)
例如十进制向八进制的数制转换 (1348)10=(2504)8，其运算过程如下：
N N div 8 N mod 8
1348 168 4
168 21 0
21 2 5
2 0 2
请利用堆栈用上述方法实现十进制向三进制的数制转换-Decimal number N, and other binary conversion is calculated on a computer to achieve the fundamental issue, the resolution many ways in which a simple algorithm based on the following principles: N = (N div d)* d+ N mod d (of which: div is divisible by operation, I mod for the sake of computing), such as decimal to octal number system conversion (1348) 10 = (2504) 8, its operation process is as follows: NN div 8 N mod 8 1348 168 4 168 21 0 21 2 5 2 0 2 to make use of the stack use of such methods to achieve the decimal to three decimal number system conversion
N=(N div d)*d+ N mod d ( 其中:div为整除运算,mod为求余运算)
例如十进制向八进制的数制转换 (1348)10=(2504)8，其运算过程如下：
N N div 8 N mod 8
1348 168 4
168 21 0
21 2 5
2 0 2
请利用堆栈用上述方法实现十进制向三进制的数制转换-Decimal number N, and other binary conversion is calculated on a computer to achieve the fundamental issue, the resolution many ways in which a simple algorithm based on the following principles: N = (N div d)* d+ N mod d (of which: div is divisible by operation, I mod for the sake of computing), such as decimal to octal number system conversion (1348) 10 = (2504) 8, its operation process is as follows: NN div 8 N mod 8 1348 168 4 168 21 0 21 2 5 2 0 2 to make use of the stack use of such methods to achieve the decimal to three decimal number system conversion
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