文件名称:mima
- 所属分类:
- 其他小程序
- 资源属性:
- [Windows] [Visual C] [源码]
- 上传时间:
- 2012-11-26
- 文件大小:
- 231kb
- 下载次数:
- 0次
- 提 供 者:
- 梁*
- 相关连接:
- 无
- 下载说明:
- 别用迅雷下载,失败请重下,重下不扣分!
介绍说明--下载内容均来自于网络,请自行研究使用
试用维吉利亚密码的方法,以ART(不区分大小写)为密钥对任意给定的字母进行加密。(加密方法:将字母a,b,c…z 对应数字0,1,2……25。明文字母m,密文c,密钥k,c=m+ki mod 26 (I=1,2,3)。例如:m="data security"对应数字"3,0,19,0,18,......,19,24";k="best" 对应数字为"1,4,18,19"密钥长度为4。c="eeltt ……r")其中c1=m1 + k1 mod 26 = 4 (e),c5=m5+k1 mod 26=19(t),c12=m12 +k4 mod 26 = 17 (r)。-Password维吉利亚trial approach to ART (not case-sensitive) as the key for any given encrypted letters. (Encryption methods: the letters a, b, c ... z corresponds to the number 0,1,2 ... ... 25. Expressly letters m, ciphertext c, the key k, c = m+ ki mod 26 (I = 1,2, 3). For example: m = " data security" corresponds to the number of " 3,0,19,0,18 ,......, 19,24" k = " best" corresponding figure for the " 1,4,18 , 19 " key length of 4. c =" eeltt ... ... r " ) in which c1 = m1+ k1 mod 26 = 4 (e), c5 = m5+ k1 mod 26 = 19 (t), c12 = m12+ k4 mod 26 = 17 (r).
(系统自动生成,下载前可以参看下载内容)
下载文件列表
mima
....\Debug
....\.....\mima.exe
....\.....\mima.obj
....\.....\mima.pdb
....\.....\mima.res
....\.....\mimaDlg.obj
....\.....\StdAfx.obj
....\.....\vc60.pdb
....\mima.aps
....\mima.clw
....\mima.cpp
....\mima.dsp
....\mima.dsw
....\mima.h
....\mima.ncb
....\mima.opt
....\mima.plg
....\mima.rc
....\mimaDlg.cpp
....\mimaDlg.h
....\ReadMe.txt
....\res
....\...\mima.rc2
....\resource.h
....\StdAfx.cpp
....\StdAfx.h
....\Debug
....\.....\mima.exe
....\.....\mima.obj
....\.....\mima.pdb
....\.....\mima.res
....\.....\mimaDlg.obj
....\.....\StdAfx.obj
....\.....\vc60.pdb
....\mima.aps
....\mima.clw
....\mima.cpp
....\mima.dsp
....\mima.dsw
....\mima.h
....\mima.ncb
....\mima.opt
....\mima.plg
....\mima.rc
....\mimaDlg.cpp
....\mimaDlg.h
....\ReadMe.txt
....\res
....\...\mima.rc2
....\resource.h
....\StdAfx.cpp
....\StdAfx.h