文件名称:DivideNum
- 所属分类：
- 其他小程序
- 资源属性：
- [Windows] [Visual.Net] [源码]
- 上传时间：
- 2012-11-26
- 文件大小：
- 581kb
- 下载次数：
- 0次
- 提 供 者：
- ins****
- 相关连接：
- 无
- 下载说明：
- 别用迅雷下载，失败请重下，重下不扣分！
介绍说明－－下载内容均来自于网络，请自行研究使用
将正整数n分为若干个不同的正整数之和，给出所有可能的拆分结果（数字相同而顺序不同的结果视为同一条结果，例如6=1+2+3和6=3+2+1，而6=2+4和6=3+3是两条符合条件的结果)
-Will be a positive integer n is divided into a number of different positive integers and, given the results of all possible split (the same as the order of the different results seen as the same results, for example, 6 = 1+ 2+ 3 and 6 = 3+ 2+ 1, and 6 = 2+ 4 and 6 = 3+ 3 is consistent with the conditions of the two results)
-Will be a positive integer n is divided into a number of different positive integers and, given the results of all possible split (the same as the order of the different results seen as the same results, for example, 6 = 1+ 2+ 3 and 6 = 3+ 2+ 1, and 6 = 2+ 4 and 6 = 3+ 3 is consistent with the conditions of the two results)
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下载文件列表
DivideNum
.........\DivideNum
.........\.........\Debug
.........\.........\DivideNum.cpp
.........\.........\DivideNum.vcproj
.........\.........\DivideNum.vcproj.ZLAB.zyz.user
.........\.........\ReadMe.txt
.........\.........\stdafx.cpp
.........\.........\stdafx.h
.........\DivideNum.ncb
.........\DivideNum.sln
.........\DivideNum
.........\.........\Debug
.........\.........\DivideNum.cpp
.........\.........\DivideNum.vcproj
.........\.........\DivideNum.vcproj.ZLAB.zyz.user
.........\.........\ReadMe.txt
.........\.........\stdafx.cpp
.........\.........\stdafx.h
.........\DivideNum.ncb
.........\DivideNum.sln