文件名称:E3744_12_0
- 所属分类:
- 其他小程序
- 资源属性:
- [Windows] [Visual C] [源码]
- 上传时间:
- 2012-11-26
- 文件大小:
- 50kb
- 下载次数:
- 0次
- 提 供 者:
- 小*
- 相关连接:
- 无
- 下载说明:
- 别用迅雷下载,失败请重下,重下不扣分!
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约瑟夫环问题约瑟夫问题的一种描述是:编号为1,2,……,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始任选一个正整数作为报数上限值m,从第一个人开始按顺时针方向自1开始顺序报数,报到m时停止报数。报m的人出列,将他的密码作为新的m值,从他在顺时针方向上的下一个人开始重新从1报数,如此下去,直至所有人全部出列为止。试设计一个程序求出出列顺序。-Joseph Joseph Central issues a descr iption of the problem is: No. 1,2, ... ..., n the n individuals according to a clockwise direction around a circle, one person holding a password (positive integer). The beginning of a positive integer optional number of upper limit, as reported m, from the first individual to embark on the clockwise direction since the beginning of the order of 1 reported that the number of reported m stop off. Reported m the person out of his password as a new m value, from his in a clockwise direction on the next person to start off again from the 1, and so on, until all that out until all. Try to design a procedure to derive the column order.
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下载文件列表
E3744_12_0
..........\a.c
..........\a.dsp
..........\a.dsw
..........\a.ncb
..........\a.opt
..........\a.plg
..........\Debug
..........\E3744_12_0.doc
..........\a.c
..........\a.dsp
..........\a.dsw
..........\a.ncb
..........\a.opt
..........\a.plg
..........\Debug
..........\E3744_12_0.doc