文件名称:scheduling
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设计一程式可输入
1、几个行程
2、每个行程各别的CPU暴冲时间(毫秒)
3、到达时间
4、优先顺序
并求出
1、FCFS
2、SJF - 不可抢先
3、SJF - 可抢先
4、Priority
5、RR
平均等待时间-Design a program may enter 1, 2 several trips, each trip of the other CPU storms red time (ms) 3, the arrival time 4, and obtained the order of priority 1, FCFS 2, SJF- can not be the first to 3, SJF-- can be the first to 4, Priority 5, RR average wait time
1、几个行程
2、每个行程各别的CPU暴冲时间(毫秒)
3、到达时间
4、优先顺序
并求出
1、FCFS
2、SJF - 不可抢先
3、SJF - 可抢先
4、Priority
5、RR
平均等待时间-Design a program may enter 1, 2 several trips, each trip of the other CPU storms red time (ms) 3, the arrival time 4, and obtained the order of priority 1, FCFS 2, SJF- can not be the first to 3, SJF-- can be the first to 4, Priority 5, RR average wait time
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scheduling.java