文件名称:AmericanGladiator

  • 所属分类:
  • Linux/Unix编程
  • 资源属性:
  • [C/C++] [源码]
  • 上传时间:
  • 2012-11-26
  • 文件大小:
  • 2kb
  • 下载次数:
  • 0次
  • 提 供 者:
  • zhous*****
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American Gladiator,You are consulting for a game show in which n contestants are pitted against n gladiators in order to see which contestants are the best. The game show aims to rank the contestants in order of strength this is done via a series of 1-on-1 matches between contestants and gladiators. If the contestant is stronger than the gladiator, then the contestant wins the match otherwise, the gladiator wins the match. If the contestant and gladiator have equal strength, then they are “perfect equals” and a tie is declared. We assume that each contestant is the perfect equal of exactly one gladiator, and each gladiator is the perfect equal of exactly one contestant. However, as the gladiators sometimes change from one show to another, we do not know the ordering of strength among the gladiators. -American Gladiator. You are consulting for a game show in which n cont estants are pitted against n gladiators in orde r to see which contestants are the best. The game show aims to rank the contestants in order of str KV this is done via a series of 1-on-1 matches between contestants and gladiators. If the con testant is stronger than the gladiator. then the contestant wins the match otherwise, the gladiator wins the match. If the contestant and gladiator have equal strength. then they are "perfect equals" and a tie is decla red. We assume that each contestant is the perfe ct equal of exactly one gladiator. and each gladiator is the perfect exact equal of ly one contestant. However, as the gladiators sometimes change from one sho w to another, we do not know the ordering of stre
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AmericanGladiator

.................\American Gladiator.cpp

.................\readme

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