文件名称:dfgshsjgdsjkl
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- JSP源码/Java
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- [Text]
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- 2012-11-26
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- 2kb
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给出3，3，8，8四个数，求一算法，程序通过这一算法，无论加减乘除，每个数用一次，计算四个数结果为24。注：不需要一种计算结果的验证。让计算机替你寻找解决方案，而不仅仅是验证而已。如round(8×8/3)+3
-3,3,8,8 are given four numbers for one algorithm, the procedure adopted by the algorithm, regardless of addition and subtraction multiplication and division, each number with time, calculated the number of results in four to 24. Note: do not need to verify the results of a calculation. Let the computer for you to find solutions, not just to verify it. Such as round (8 × 8/3)+ 3
-3,3,8,8 are given four numbers for one algorithm, the procedure adopted by the algorithm, regardless of addition and subtraction multiplication and division, each number with time, calculated the number of results in four to 24. Note: do not need to verify the results of a calculation. Let the computer for you to find solutions, not just to verify it. Such as round (8 × 8/3)+ 3
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