文件名称:AnEasyProblem
- 所属分类：
- 数值算法/人工智能
- 资源属性：
- [Windows] [Visual C] [源码]
- 上传时间：
- 2012-11-26
- 文件大小：
- 229kb
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- L*
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ACM试题An Easy Problem
Descr iption
As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".
-An Easy Problem Descr iption As we kno wn. data stored in the computers i n binary form. T he problem we discuss now is about the positive i ntegers and its binary form. Given a positive in teger I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1's in whose binary form is the sa me as that in the binary form of I. For example, if "78" is given. we can write out its binary form. "1001110." This binary form has 4 1 s. The minimu m integer, which is greater than "1001110" and also contai ns 4 1's, is "1010011", i.e., "83", so you should output "83."
Descr iption
As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".
-An Easy Problem Descr iption As we kno wn. data stored in the computers i n binary form. T he problem we discuss now is about the positive i ntegers and its binary form. Given a positive in teger I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1's in whose binary form is the sa me as that in the binary form of I. For example, if "78" is given. we can write out its binary form. "1001110." This binary form has 4 1 s. The minimu m integer, which is greater than "1001110" and also contai ns 4 1's, is "1010011", i.e., "83", so you should output "83."
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An Easy Problem
...............\An Easy Problem
...............\...............\An Easy Problem.cpp
...............\...............\An Easy Problem.dsp
...............\...............\An Easy Problem.dsw
...............\...............\An Easy Problem.ncb
...............\...............\An Easy Problem.opt
...............\...............\An Easy Problem.plg
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...............\An Easy Problem
...............\...............\An Easy Problem.cpp
...............\...............\An Easy Problem.dsp
...............\...............\An Easy Problem.dsw
...............\...............\An Easy Problem.ncb
...............\...............\An Easy Problem.opt
...............\...............\An Easy Problem.plg
...............\...............\Debug