文件名称:Recursive_integer_division
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递归法求解整数划分。
整数划分,是指把一个正整数n写成如下形式:
n=m1+m2+…+mi (其中mi为正整数,并且1 <= mi <= n),则{m1,m2,...,mi}为n的一个划分。
如果{m1,m2,...,mi}中的最大值不超过m,即max(m1,m2,...,mi)<=m,则称它属于n的一个m划分。这里我们记n的m划分的个数为f(n,m)-Recursive method integer division. Integer division, refers to a positive integer n written as follows: n = m1+m2+ ...+mi (where mi is a positive integer, and 1 < = mi < = n), then {m1, m2, ..., mi} is a division of n. If {m1, m2, ..., mi} does not exceed the maximum value of m, i.e., max (m1, m2, ..., mi) < = m, m n is said that it belongs to a division. Where m is the number of division n our mind is f (n, m)
整数划分,是指把一个正整数n写成如下形式:
n=m1+m2+…+mi (其中mi为正整数,并且1 <= mi <= n),则{m1,m2,...,mi}为n的一个划分。
如果{m1,m2,...,mi}中的最大值不超过m,即max(m1,m2,...,mi)<=m,则称它属于n的一个m划分。这里我们记n的m划分的个数为f(n,m)-Recursive method integer division. Integer division, refers to a positive integer n written as follows: n = m1+m2+ ...+mi (where mi is a positive integer, and 1 < = mi < = n), then {m1, m2, ..., mi} is a division of n. If {m1, m2, ..., mi} does not exceed the maximum value of m, i.e., max (m1, m2, ..., mi) < = m, m n is said that it belongs to a division. Where m is the number of division n our mind is f (n, m)
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Debug\CL.read.1.tlog
.....\CL.write.1.tlog
.....\link-cvtres.read.1.tlog
.....\link-cvtres.write.1.tlog
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.....\link-rc.write.1.tlog
.....\link.read.1.tlog
.....\link.write.1.tlog
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.....\递归法求解整数划分.lastbuildstate
.....\递归法求解整数划分.log
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递归法求解整数划分.cpp
递归法求解整数划分.vcxproj
递归法求解整数划分.vcxproj.filters
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