文件名称:jicha
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给定n个正整数数列,进行如下操作:每次删去两个数 a和b,添加1个数 a*b+1,直到只剩1个数N。在所有的这样的N中,有1个最大Max的和最小的Min,M=Max-Min是极差。设计程序计算 M
-Given n positive integers, proceed as follows: each time deleting two numbers a and b, add a number of a* b+1 until only a number of N. All this N, a Max and minimum Min, M = Max-Min is very poor. Design program to calculate M
-Given n positive integers, proceed as follows: each time deleting two numbers a and b, add a number of a* b+1 until only a number of N. All this N, a Max and minimum Min, M = Max-Min is very poor. Design program to calculate M
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jicha.cpp