文件名称:jophous
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约瑟夫斯(Josephus)问题的一种描述是:编号为1,2,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始任选一个正整数作为报数上限值m,从第一个人开始按顺时针方向自1开始报数,报到m时停止报数。报m的人出列,将他的密码作为新的m值,从他在顺时针方向下一个人开始重新从1报数,如此下去,直至所有的人全部出列为止。试设计一个程序,按出列顺序印出各人编号。 -Josephus (Josephus) a descr iption of the problem is: Numbers for 1, 2,..., n n individual clockwise around a circle, each holding a password (positive integer).At first choose a positive integer as the upper limit count off m, since the first man since 1 count off, clockwise when reporting for m stop count off.To dequeue m, his password as the new m values, in a clockwise direction him the next person started to count off 1, so go on, until all the people all dequeue.Try to design a program to print out according to the order number.
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顺序表约瑟夫斯.c