一位数学老师，经常写一些乘法算式，看起来是不对的，但经过进制转换却是正确的。比如5*8＝34，如果是12进制的运算则是正确的。

你的目标是写出一个程序，找到正确的进制(介于2和16之间)，如果找不到则输出0。注意，若有多种情况，则输出最小进制。如10*10=100，则输出2。

第一种：10*10=100输出10，不符合输出2的结果

先计算出两个数乘积的十进制数，再将此十进制数转换为2到16的进制数，依次与原先给出的结果值比较，若相等，则输出当前为几进制，若都不相等，则输出0-A math teacher, often write some multiplication facts, it appears to be wrong, but after binary conversion is correct. For example, 5* 8 = 34, if it is 12-ary calculation is correct. Your goal is to write a program to find the right hex (between 2 and 16), the output is 0 if not found. Note that if many cases, the minimum output hex. Such as 10* 10 = 100, output 2. The first is: 10* 10 = 100 outputs 10, does not comply with the output of 2 decimal first calculate the product of two numbers, and then convert this decimal to hexadecimal 2-16 sequentially given with the original The resulting value comparison, if the same, then the output current of a few decimal, if not equal, then output 0