文件名称:diffeehellmanPROGRAM
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Example 1. To find 1537 x 4248 modulo 10, you could multiply out and take the last digit, but a better way would be to replace 1537 by 7 and 4248 by 8 to start, find 7 x 8 = 56, and then take 56 mod 10 to get 6 as the answer.
A handy standard notation is to write a tex2html_wrap_inline39 b (mod m) if a and b have the same remainder modulo m. This is read a is congruent to b modulo m . In this notation the example just mentioned looks like this: 1537 x 4248 tex2html_wrap_inline39 7 x 8 = 56 tex2html_wrap_inline39 6 (mod 10).-Example 1. To find 1537 x 4248 modulo 10, you could multiply out and take the last digit, but a better way would be to replace 1537 by 7 and 4248 by 8 to start, find 7 x 8 = 56, and then take 56 mod 10 to get 6 as the answer.
A handy standard notation is to write a tex2html_wrap_inline39 b (mod m) if a and b have the same remainder modulo m. This is read a is congruent to b modulo m . In this notation the example just mentioned looks like this: 1537 x 4248 tex2html_wrap_inline39 7 x 8 = 56 tex2html_wrap_inline39 6 (mod 10).
A handy standard notation is to write a tex2html_wrap_inline39 b (mod m) if a and b have the same remainder modulo m. This is read a is congruent to b modulo m . In this notation the example just mentioned looks like this: 1537 x 4248 tex2html_wrap_inline39 7 x 8 = 56 tex2html_wrap_inline39 6 (mod 10).-Example 1. To find 1537 x 4248 modulo 10, you could multiply out and take the last digit, but a better way would be to replace 1537 by 7 and 4248 by 8 to start, find 7 x 8 = 56, and then take 56 mod 10 to get 6 as the answer.
A handy standard notation is to write a tex2html_wrap_inline39 b (mod m) if a and b have the same remainder modulo m. This is read a is congruent to b modulo m . In this notation the example just mentioned looks like this: 1537 x 4248 tex2html_wrap_inline39 7 x 8 = 56 tex2html_wrap_inline39 6 (mod 10).
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