文件名称:TheDesignof35kVGridRelayprotection
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本压缩包 包含 任务书、论文以及答辩ppt,虽说是课程设计,但是按照毕业设计书写,内容充实
本次课程设计主要是对象湖变的电网进行保护整定,对d1至d6共6个地方进行了最大方式与最小方式运行情况下的短路电流计算。计算完短路电流后,对L1至L5共5条线路进行电流保护整定。但是由于线路较短,线路阻抗较小。经计算后均不适合三段式电流保护。所以采取了纵联差动保护作为主保护,定时限过电流保护作为后备保护。对于变压器,采用纵联差动保护与气体保护共同作为主保护,过负荷保护作为后备保护。-The curriculum design is the object variable grid lake protection setting of D1 to D6, 6 places for the maximum and minimum operation mode under the condition of short-circuit current calculation. Calculation of short-circuit current after the end, L1 to L5 a total of 5 lines of current protection setting. But because of shorter lines, line impedance is small. The calculations are not suitable for three phase current protection. So take a longitudinal differential protection as the main protection, timing and limiting current protection as a back-up protection. For transformers, using longitudinal differential protection and gas protection as the main protection, overload protection as a back-up protection.
本次课程设计主要是对象湖变的电网进行保护整定,对d1至d6共6个地方进行了最大方式与最小方式运行情况下的短路电流计算。计算完短路电流后,对L1至L5共5条线路进行电流保护整定。但是由于线路较短,线路阻抗较小。经计算后均不适合三段式电流保护。所以采取了纵联差动保护作为主保护,定时限过电流保护作为后备保护。对于变压器,采用纵联差动保护与气体保护共同作为主保护,过负荷保护作为后备保护。-The curriculum design is the object variable grid lake protection setting of D1 to D6, 6 places for the maximum and minimum operation mode under the condition of short-circuit current calculation. Calculation of short-circuit current after the end, L1 to L5 a total of 5 lines of current protection setting. But because of shorter lines, line impedance is small. The calculations are not suitable for three phase current protection. So take a longitudinal differential protection as the main protection, timing and limiting current protection as a back-up protection. For transformers, using longitudinal differential protection and gas protection as the main protection, overload protection as a back-up protection.
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下载文件列表
课设\35kV电网继电保护设计.docx
....\答辩ppt.pptx
....\课程设计任务书.doc
课设
....\答辩ppt.pptx
....\课程设计任务书.doc
课设