文件名称:ProjectCode

  • 所属分类:
  • 数值算法/人工智能
  • 资源属性:
  • [C/C++] [源码]
  • 上传时间:
  • 2012-11-26
  • 文件大小:
  • 37kb
  • 下载次数:
  • 0次
  • 提 供 者:
  • sl***
  • 相关连接:
  • 下载说明:
  • 别用迅雷下载,失败请重下,重下不扣分!

介绍说明--下载内容均来自于网络,请自行研究使用

The objective is to find out the time at which the rocket reaches a speed of 1000m/s (3600km/hr).

Analysis

We know the following:

*  Initial mass of the rocket and fuel, 160000kg, or 160 metric tons.

*  Fuel combustion exhaust velocity relative to the rocket is assumed to be constant at 2200m/s

*  Fuel combustion rate is a constant 2680kg/sec2

*  Gravitational acceleration is 9.8m/sec2

The following formula is used to calculate the upward velocity of the rocket while the fuel is providing thrust:

V = u*loge(m0/(m0-qt))-g*t

Now substituting the values in the formula we get:

1000 = 2200*log(160000 / (160000 – 9.8*t)) – 9.8*t



which is too difficult to solve analytically so we use Bisection root-finding method. The source code is for a program that solves this problem with the given parameters.
(系统自动生成,下载前可以参看下载内容)

下载文件列表

ProjectCode

...........\.dep.inc

...........\build

...........\.....\Debug

...........\.....\.....\Cygwin_4.x-Windows

...........\.....\.....\..................\main.o

...........\.....\.....\..................\main.o.d

...........\dist

...........\....\Debug

...........\....\.....\Cygwin_4.x-Windows

...........\....\.....\..................\numericalproject.exe

...........\main.cpp

...........\Makefile

...........\nbproject

...........\.........\configurations.xml

...........\.........\Makefile-Debug.mk

...........\.........\Makefile-impl.mk

...........\.........\Makefile-Release.mk

...........\.........\Makefile-variables.mk

...........\.........\Package-Debug.bash

...........\.........\Package-Release.bash

...........\.........\private

...........\.........\.......\configurations.xml

...........\.........\.......\Makefile-variables.mk

...........\.........\.......\private.xml

...........\.........\project.xml

相关说明

  • 本站资源为会员上传分享交流与学习,如有侵犯您的权益,请联系我们删除.
  • 本站是交换下载平台,提供交流渠道,下载内容来自于网络,除下载问题外,其它问题请自行百度更多...
  • 请直接用浏览器下载本站内容,不要使用迅雷之类的下载软件,用WinRAR最新版进行解压.
  • 如果您发现内容无法下载,请稍后再次尝试;或者到消费记录里找到下载记录反馈给我们.
  • 下载后发现下载的内容跟说明不相乎,请到消费记录里找到下载记录反馈给我们,经确认后退回积分.
  • 如下载前有疑问,可以通过点击"提供者"的名字,查看对方的联系方式,联系对方咨询.

相关评论

暂无评论内容.

发表评论

*主  题:
*内  容:
*验 证 码:

源码中国 www.ymcn.org