文件名称:matlab_queue_system
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自己写的用Matlab模拟一个缓冲区大小（包括正在服务的那个）为10的随机排队系统。
（1）到达过程是的泊松过程（到达速率为Mu），服务时间服从独立指数分布（均值为1/Lamda）。
对Mu//Lamda=0.2，Mu//Lamda=0.8和Mu//Lamda=1.1三种情况进行仿真，求出队列中接受服务用户为n的概率P(n), n=0,...,10。并与理论结果进行比较。
（2）假设到达过程为均匀过程（到达速率为Mu），服务时间服从独立瑞利分布（均值为1/Lamda）。-yourself writing a simulation using Matlab buffer size (including services that are) for the following 10 Machine queuing system. (1) arrival process is the Poisson process (arrival rate of Mu), submit to independent service index distribution (mean of 1 / Lamda). Right Mu / / Lamda = 0.2, Mu / / Lamda = 0.8 and the Mu / / = 1.1 Lamda three of the simulation, Queue calculated users receive services n the probability P (n), n = 0 ,..., 10. And with the theoretical results. (2) It is assumed that the arrival process for the uniform process (arrival rate of Mu), submit to independent service Rayleigh distribution (mean of 1 / Lamda).
（1）到达过程是的泊松过程（到达速率为Mu），服务时间服从独立指数分布（均值为1/Lamda）。
对Mu//Lamda=0.2，Mu//Lamda=0.8和Mu//Lamda=1.1三种情况进行仿真，求出队列中接受服务用户为n的概率P(n), n=0,...,10。并与理论结果进行比较。
（2）假设到达过程为均匀过程（到达速率为Mu），服务时间服从独立瑞利分布（均值为1/Lamda）。-yourself writing a simulation using Matlab buffer size (including services that are) for the following 10 Machine queuing system. (1) arrival process is the Poisson process (arrival rate of Mu), submit to independent service index distribution (mean of 1 / Lamda). Right Mu / / Lamda = 0.2, Mu / / Lamda = 0.8 and the Mu / / = 1.1 Lamda three of the simulation, Queue calculated users receive services n the probability P (n), n = 0 ,..., 10. And with the theoretical results. (2) It is assumed that the arrival process for the uniform process (arrival rate of Mu), submit to independent service Rayleigh distribution (mean of 1 / Lamda).
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压缩包 : 83390053matlab_queue_system.rar 列表 pmean.m queue.m