文件名称:fapaichengxu
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Java编程 做一个发牌的程序
首先是创造牌（牌会有1-6付选择），然后洗牌：将牌一分二，由( x(k+1) = (5xk mod 16) + 1 )来依次从两边取牌，直至牌不够，就将牌合起来。然后将牌发给2-60人，每人5张牌。
可以使用java.util.List<E>, java.util.Collection<E>, java.util.Iterator<E>, and java.util.ListIterator，最好用Arraylist来做。像牌数和人数，由输入决定
-Java program to do a licensing program is to create the first card (brand-sum option would be 1-6), and then shuffle: The license for one sub-2, from (x (k+1) = (5xk mod 16)+ 1 ) to turn from both sides to take a license until the license is not enough, it will be brand together. Then the card issued to 2-60, with each person 5 cards. You can use java.util.List <E> , Java.util.Collection <E> , Java.util.Iterator <E> , And java.util.ListIterator, preferably Arraylist do. Such as the number of licenses and the number of input decision
首先是创造牌（牌会有1-6付选择），然后洗牌：将牌一分二，由( x(k+1) = (5xk mod 16) + 1 )来依次从两边取牌，直至牌不够，就将牌合起来。然后将牌发给2-60人，每人5张牌。
可以使用java.util.List<E>, java.util.Collection<E>, java.util.Iterator<E>, and java.util.ListIterator，最好用Arraylist来做。像牌数和人数，由输入决定
-Java program to do a licensing program is to create the first card (brand-sum option would be 1-6), and then shuffle: The license for one sub-2, from (x (k+1) = (5xk mod 16)+ 1 ) to turn from both sides to take a license until the license is not enough, it will be brand together. Then the card issued to 2-60, with each person 5 cards. You can use java.util.List <E> , Java.util.Collection <E> , Java.util.Iterator <E> , And java.util.ListIterator, preferably Arraylist do. Such as the number of licenses and the number of input decision
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发牌程序.doc