搜索资源列表
布线问题(分支限界算法应用)
- 六 程序实现: #include <stdio.h> typedef struct { int row int col }Position int FindPath (Position start, Position finish, int &PathLen, Position *&path) { //计算从起始位置start到目标位置finish的最短布线路径,找到返回1,否则,返回0
bpsk_dsss
- There are two files in the zip folder. bpsk_spread.m and jakesmodel.m Steps for simulation: 1] Run jakesmodel.m first 2] Then run bpsk_spread.m . 3] Note that during the first run bpsk_spread.m has no rayleigh fa
GT-Grid[1].vs.EXT-Grid
- 纯JS的数据列表 6000行数据 需要9秒
gt3.0.2-core-src.tar
- GT(globus toolkit)网格开发平台(含源代码)-GT (GLOBUS toolkit) grid development platform (including source code)
2-8
- 在9(3*3)个方格的方阵中填入数字1到N(N>=10)内的某9个数字 每个方格填一个整数,要求相邻两个方格的两个整数之和为质数。 试求所有的解-in 9 (3 * 3) grid matrix to fill out a number of N (Ngt; = 10) of a nine figures each box filled an integral require two adjacent box at the two
gt3.0.2-core-src.tar
- GT(globus toolkit)网格开发平台(含源代码)-GT (GLOBUS toolkit) grid development platform (including source code)
2-8
- 在9(3*3)个方格的方阵中填入数字1到N(N>=10)内的某9个数字 每个方格填一个整数,要求相邻两个方格的两个整数之和为质数。 试求所有的解-in 9 (3* 3) grid matrix to fill out a number of N (Ngt; = 10) of a nine figures each box filled an integral require two adjacent box at the two
布线问题(分支限界算法应用)
- 六 程序实现: #include <stdio.h> typedef struct { int row int col }Position int FindPath (Position start, Position finish, int &PathLen, Position *&path) { //计算从起始位置start到目标位置finish的最短布线路径,找到返回1,否则,返回0
bpsk_dsss
- There are two files in the zip folder. bpsk_spread.m and jakesmodel.m Steps for simulation: 1] Run jakesmodel.m first 2] Then run bpsk_spread.m . 3] Note that during the first run bpsk_spread.m has no rayleigh fa
GT-Grid[1].vs.EXT-Grid
- 纯JS的数据列表 6000行数据 需要9秒-JS pure data list 6000 line data needs 9 seconds
Describing_Globus_Toolkit_Version_4
- We discuss in turn the applications that motivate the development of GT4 and related tools the four tasks involved in building Grids: design, deployment, application, operations GT4 structure, including its Web servi
MymeterfromPaintBox
- 本范例采用TPaintBox控件派生出仪表控件。 文件说明:PaintGrid.pas 网格型仪表控件源文件 Mymeter.pas 圆型仪表控件源文件 Project1是这两个控件的使用范例。 该范例可方便Delphi的控件开发初学者,对仪表 开发或对PaintBox的使用有学习需要的朋友。 控件的安装方法: 1.进入菜单->Component->install Component
dist_20080422
- GT-Grid 1.0 alpha 1 特性: ajax实现 (翻页,数据的crud基于ajax技术) 固定表头和工具栏 可调整列宽: 拖动列表表头之间的分割线. 可调整相对位置: 按住ctrl 键不放,拖动列表表头 支持按列排序,点击表头栏,将在 acs desc 默认排序 三者之间切换. 列隐藏 列冻结 支持列编组.(建议先排序后再编组) 支持行选择(按ctrl多选),选择方式类似在win
gt-grid
- gt_grid,datagrid,提供列表数据显示,翻页排序-gt_grid, datagrid, provide a list data, flip sort
GT_Grid_Demo_20070928
- gt-grid demo 与ecside表格源码。-gt-grid demo form with the ecside source.
GT4Java
- 该文档为《Globus Toolkit4:java网格服务编程》的过程解读,一直更新中... ...从并行计算的高层服务认识,并深入认识GT的架构从而更加深入的理解网格计算的意义-The document for the " Globus Toolkit4: java programming grid services," the process of interpretation, has been updated
QASk
- Quaternary Amplitude Shift Keying clear all M=3 NPoints=input( Enter the number of points>> ) NumberBits=input( Enter the number of points per bit>> ) Signal Constellation of ASK fo
Untitled5
- Quaternary Amplitude Shift Keying clear all M=3 NPoints=input( Enter the number of points>> ) NumberBits=input( Enter the number of points per bit>> ) Signal Constellation of ASK fo
gtgrid
- gtgrid的练习,从基本到难的,由浅入深-gtgrid traning
GT
- 龟兔赛跑: 普通格,共100格 龟:每次随机移动1至3格 兔子:每次随机移动1至6格 每20格会随机出现以下功能格各一次(不会在同一格内出现两种或两种以上功能) 功能格:(**和^^可以连续执行,@@和==不能连续执行) **幸运星格:选手可再行动一次 @@地雷格:兔子回到上数两个地雷格,龟回到上一地雷格(若后方无地雷格则回到起点) ==传送格:兔子到达下一传送格,龟到达下数两个