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PCF8574KEY20
- PCF8574KEY20.ASM 20键扫描加6位数码显示的实验程序B: R1,存放扫描行的键值:各行首键的值分别为 #0,#4,#8,#12 (共有四行) R2,存放PB口送扫描的数。 R5,存放扫描列的键值: #0,#1,#2,#3 (共有四列)-PCF8574KEY20.ASM 20 key scan plus six digital display of experimental procedure B: R
PCF8591AD
- PCF8591AD.C PCF8591的AD转换实验. /*芯片PCF8951共有四个A/D输入通道:AD0,AD1,AD2,AD3,分别与四个电位器(R1,R2,R3,R4)连接,用以调节电位器的输出电压。其中AD0通道既可测量电位器输出电压,也可用于测量从J1插座输入的外接电压,须用开关J2加以选择。J4插座提供由PCF8591输出的时钟方波信号。SAA1064驱动四个数码管显示一路AD转换后得到的数据-PCF8591AD.C
BaiduNewPlayer
- 29 次 源码介绍: 百度最新音乐播放器,专用来下载百度最新发布的音乐,经测试Windows Server 2003 R2 企业版 通过[至于其他平台,还没测试过呢! -29 Source Descr iption: Baidu latest music player, dedicated to download the latest music Baidu, tested Windows Server 200
Windows_Mobile_5_0_SDK_R2_amples
- 微软手机程序开发原版SDK示例Windows_Mobile_5.0_SDK_ R2 _amples-Microsoft Windows Mobile SDK Windows_Mobile_5.0_SDK_ R2 _amples
01259361tubianlideyanshi
- 图的遍历的演示(c 语言 数据结构课程设计题) /*定义图*/ typedef struct{ int V[M] int R[M][M] int vexnum }Graph /*创建图*/ void creatgraph(Graph *g,int n) { int i,j,r1,r2 g->vexnum=n /*顶点用i表示*/ for(i=1 i<=n i++) { g->V[i]=i } /*初始化R*/ for(
25175sdxh
- 主要功能: 学生账号:001,001 宿管:xg,xg 管理员:admin,admin 学生用户: 学号>001 房号>睿智楼 R2-201 宿舍总人数>1人 查询的月份>价格 宿舍管理员: [宿舍 睿智楼|R 6楼 1号 缴费月份 2006年1月 电抄表 热水抄表 冷水抄表] 确认缴费数据[房间 缴费时间 电抄表 电费 热水抄表 热水费 冷水抄表 冷水费 是否已缴费 ] 修改宿舍
R2XF
- 这也是一个QQ音速游戏外挂的源码.. 并非本人自己做的.具体不太清楚. -This is a QQ game sound source plug my own do not ... The concrete is less clear.
R2-NETXM
- 也是一个QQ音速外挂的源码. 我自己写的.虽然没有别人写的那么完美. 有需要的拿去研究吧-QQ is a sound plug-in source code. I wrote it myself. Though not written by someone else so perfect. Naqu in need of it
EVM3530BSPUseGuide
- This manual provides installation, information, usage and operating instructions for a Windows Embedded CE 6.0 R2 BSP built for the Texas Instruments OMAP35xx Evaluation Module (EVM). It also includes information and
circle
- 屏幕中央有一个半径为R1的大圆和一个同心的且半径为R2的小圆,同时在大圆和小圆中间均匀分布着12个与大圆和小圆相切的圆-The screen has a radius R1 of the great circle and a concentric radius R2 and the small round, while in the great circle and small round evenly distributed amon
MATLAB-basic-intensive-training
- 运用MATLAB编程并结合simulink解决简单的电路问题。 自选题目:图1所示为典型的直流电阻电路[3], 含有电压控制的受控电流源VCCS,其中,R1=1Ω,R2= 2Ω, R3=3Ω,US=10V, IS=15A, VCCS= ,现需分析计算电流i1和电压u2 -Combined with the use of MATLAB simulink program to solve simple circuit problem
CameraDemo
- 6410 WinCE6.0 R2 上的CAMERA 程序的源码,有很大的参考价值-6410 WinCE6.0 R2 on the CAMERA program source code, there is a great reference value
s3c6410-yuv-capture
- 自己开发的基于华恒S3C6410-R2开发板的yuv图像采集程序,提供c源程序和MAKEFILE,头文件开发板配套资料有,使用时.c文件要改名为cam2fb.c,已产品化-Their development huaheng S3C6410-R2 based on development board yuv image capture program, providing c source code and MAKEFILE, the f
s3c6410-h264-encode-ok
- 已产品化代码,用华恒S3C6410-R2开发板采集视频并压缩为H264格式,不带IDR帧,提供c源程序和MAKEFILE,头文件开发板配套资料有,使用时.c文件要改名为cam2fb.c-Product of the code has been used huaheng S3C6410-R2 development board acquisition and compression for the H264 video format, w
s3c6410-h264-IDR-encode-ok
- 这是上一个代码的优化,加了IDR帧编码,适合不稳定网络(如移动通信网),已产品化,基于华恒S3C6410-R2开发板采集视频并压缩为H264格式,带IDR帧,使用时.c文件要改名为cam2fb.c-This is a code optimization, plus the IDR fr a me coding for unstable networks (such as mobile communications network), h
SQLServer2008R2eBook
- SQL Server 2008 R2 e-book
JiaoChaShang
- 文本挖掘中交叉熵算法实现,通过词汇左右出现的概率来计算交叉熵-Text mining cross entropy algorithm,The task of part2of2speech iden t if icat ion is to au tomat ically assign a part2of2speech tag to an unknow n wo rd w ith emp ty part2of2speech info r
Pro-SQL-Server-2008-Service-Broker
- Pro Biztalk BAM 2009 - Guide to develop Service Broker solutions using Microsoft Service Broker of Microsoft SQL Server 2008 R2
Pro-SQL-Server-2008-XML
- Pro Biztalk BAM 2009 - Guide to develop solutions with XML using XML Data type of Microsoft SQL Server 2008 R2
cpp1
- C,C++ Questions 1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived object,. calling of that virtual method will result in wh